3-5b+3b=-2-2(1-b)

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Solution for 3-5b+3b=-2-2(1-b) equation: 



3-5b+3b=-2-2(1-b)

We move all terms to the left:

3-5b+3b-(-2-2(1-b))=0

We add all the numbers together, and all the variables

-5b+3b-(-2-2(-1b+1))+3=0

We add all the numbers together, and all the variables

-2b-(-2-2(-1b+1))+3=0



We calculate terms in parentheses: -(-2-2(-1b+1)), so:

-2-2(-1b+1)

determiningTheFunctionDomain
-2(-1b+1)-2

We multiply parentheses

2b-2-2

We add all the numbers together, and all the variables

2b-4

Back to the equation:

-(2b-4)



We get rid of parentheses

-2b-2b+4+3=0

We add all the numbers together, and all the variables

-4b+7=0

We move all terms containing b to the left, all other terms to the right

-4b=-7

b=-7/-4

b=1+3/4

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