3-5/6x=2x+8

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Solution for 3-5/6x=2x+8 equation:



3-5/6x=2x+8
We move all terms to the left:
3-5/6x-(2x+8)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
We get rid of parentheses
-5/6x-2x-8+3=0
We multiply all the terms by the denominator
-2x*6x-8*6x+3*6x-5=0
Wy multiply elements
-12x^2-48x+18x-5=0
We add all the numbers together, and all the variables
-12x^2-30x-5=0
a = -12; b = -30; c = -5;
Δ = b2-4ac
Δ = -302-4·(-12)·(-5)
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{165}}{2*-12}=\frac{30-2\sqrt{165}}{-24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{165}}{2*-12}=\frac{30+2\sqrt{165}}{-24} $

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