3-5(6-7x)=(8x-11)-4(9x-25)

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Solution for 3-5(6-7x)=(8x-11)-4(9x-25) equation: 



3-5(6-7x)=(8x-11)-4(9x-25)

We move all terms to the left:

3-5(6-7x)-((8x-11)-4(9x-25))=0

We add all the numbers together, and all the variables

-5(-7x+6)-((8x-11)-4(9x-25))+3=0

We multiply parentheses

35x-((8x-11)-4(9x-25))-30+3=0



We calculate terms in parentheses: -((8x-11)-4(9x-25)), so:

(8x-11)-4(9x-25)

We multiply parentheses

(8x-11)-36x+100

We get rid of parentheses

8x-36x-11+100

We add all the numbers together, and all the variables

-28x+89

Back to the equation:

-(-28x+89)



We add all the numbers together, and all the variables

35x-(-28x+89)-27=0

We get rid of parentheses

35x+28x-89-27=0

We add all the numbers together, and all the variables

63x-116=0

We move all terms containing x to the left, all other terms to the right

63x=116

x=116/63

x=1+53/63

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