3-4i/5+2i=5+2i/5+2i

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Solution for 3-4i/5+2i=5+2i/5+2i equation: 



3-4i/5+2i=5+2i/5+2i

We move all terms to the left:

3-4i/5+2i-(5+2i/5+2i)=0



Domain of the equation: 5+2i)!=0

We move all terms containing i to the left, all other terms to the right

2i)!=-5

i!=-5/1

i!=-5

i∈R



We add all the numbers together, and all the variables

-4i/5+2i-(2i+2i/5+5)+3=0

We add all the numbers together, and all the variables

2i-4i/5-(2i+2i/5+5)+3=0

We get rid of parentheses

2i-4i/5-2i-2i/5-5+3=0

We multiply all the terms by the denominator


2i*5-4i-2i*5-2i-5*5+3*5=0

We add all the numbers together, and all the variables

-6i+2i*5-2i*5-10=0

Wy multiply elements

-6i+10i-10i-10=0

We add all the numbers together, and all the variables

-6i-10=0

We move all terms containing i to the left, all other terms to the right

-6i=10

i=10/-6

i=-1+2/3

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