3-4f=2+6(-6+2f)

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Solution for 3-4f=2+6(-6+2f) equation: 



3-4f=2+6(-6+2f)

We move all terms to the left:

3-4f-(2+6(-6+2f))=0

We add all the numbers together, and all the variables

-4f-(2+6(2f-6))+3=0



We calculate terms in parentheses: -(2+6(2f-6)), so:

2+6(2f-6)

determiningTheFunctionDomain
6(2f-6)+2

We multiply parentheses

12f-36+2

We add all the numbers together, and all the variables

12f-34

Back to the equation:

-(12f-34)



We get rid of parentheses

-4f-12f+34+3=0

We add all the numbers together, and all the variables

-16f+37=0

We move all terms containing f to the left, all other terms to the right

-16f=-37

f=-37/-16

f=2+5/16

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