3-4/9(5+7k)=-129

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Solution for 3-4/9(5+7k)=-129 equation: 



3-4/9(5+7k)=-129

We move all terms to the left:

3-4/9(5+7k)-(-129)=0



Domain of the equation: 9(5+7k)!=0

k∈R



We add all the numbers together, and all the variables

-4/9(7k+5)+3-(-129)=0

We add all the numbers together, and all the variables

-4/9(7k+5)+132=0

We multiply all the terms by the denominator


132*9(7k+5)-4=0

Wy multiply elements

1188k(7-4=0

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