3-4(y+2)=6+4(2y+1)

Solution for 3-4(y+2)=6+4(2y+1) equation:

3-4(y+2)=6+4(2y+1)

We move all terms to the left:

3-4(y+2)-(6+4(2y+1))=0

We multiply parentheses

-4y-(6+4(2y+1))-8+3=0


We calculate terms in parentheses: -(6+4(2y+1)), so:

6+4(2y+1)

determiningTheFunctionDomain
4(2y+1)+6

We multiply parentheses

8y+4+6

We add all the numbers together, and all the variables

8y+10

Back to the equation:

-(8y+10)


We add all the numbers together, and all the variables

-4y-(8y+10)-5=0

We get rid of parentheses

-4y-8y-10-5=0

We add all the numbers together, and all the variables

-12y-15=0

We move all terms containing y to the left, all other terms to the right

-12y=15

y=15/-12

y=-1+1/4