3-4(b+2)=b-(b-3)

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Solution for 3-4(b+2)=b-(b-3) equation: 



3-4(b+2)=b-(b-3)

We move all terms to the left:

3-4(b+2)-(b-(b-3))=0

We multiply parentheses

-4b-(b-(b-3))-8+3=0



We calculate terms in parentheses: -(b-(b-3)), so:

b-(b-3)

We get rid of parentheses

b-b+3

We add all the numbers together, and all the variables

3

Back to the equation:

-(3)



We add all the numbers together, and all the variables

-4b-8=0

We move all terms containing b to the left, all other terms to the right

-4b=8

b=8/-4

b=-2

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