If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3-3/4y=1/4y-7
We move all terms to the left:
3-3/4y-(1/4y-7)=0
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 4y-7)!=0We get rid of parentheses
y∈R
-3/4y-1/4y+7+3=0
We multiply all the terms by the denominator
7*4y+3*4y-3-1=0
We add all the numbers together, and all the variables
7*4y+3*4y-4=0
Wy multiply elements
28y+12y-4=0
We add all the numbers together, and all the variables
40y-4=0
We move all terms containing y to the left, all other terms to the right
40y=4
y=4/40
y=1/10
| 17-8h-h=-5h-3 | | 1/2m+5=-7+3/2m | | 5n=2n+39 | | m+m-7m=0 | | (2a+3)+(3a-7)=5a-4 | | 1.85x=5.30 | | 65=5u+55 | | u/7=8/3 | | 8x+12-3x375x=25 | | 17=-8+u/5 | | 6y-71=y+54 | | -8x+3(x+4)=22 | | 30=7w-12 | | 18=7w | | 9x+2x-8-5=16 | | 25=6v-89 | | 54n=-81 | | 15-(-8x)=3x+25 | | 4b=9-3b | | -3x-15=-8x-35 | | -3x+15=-8x-35 | | 72=7x+x-8 | | -2x-12=-6x+20 | | -2x+12=-6x+20 | | 90.4=8(m+3.1) | | 10x-8=2x+32 | | 200=5(4s+4) | | ((3*2^0.5-3)+(2*2^0.5-3)i)^2+(6+10i)*((3*2^0.5-3)+(2*2^0.5-3)i)-(26-6i)=0 | | -18=16+x | | 2(-x+4)=4x | | -30=5x-10 | | 4x/3+3/2=5+2x/3 |