3-3(y-4)=2y+2

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Solution for 3-3(y-4)=2y+2 equation: 



3-3(y-4)=2y+2

We move all terms to the left:

3-3(y-4)-(2y+2)=0

We multiply parentheses

-3y-(2y+2)+12+3=0

We get rid of parentheses

-3y-2y-2+12+3=0

We add all the numbers together, and all the variables

-5y+13=0

We move all terms containing y to the left, all other terms to the right

-5y=-13

y=-13/-5

y=2+3/5

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