3-3(x-5)=2(2x-5)

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Solution for 3-3(x-5)=2(2x-5) equation: 



3-3(x-5)=2(2x-5)

We move all terms to the left:

3-3(x-5)-(2(2x-5))=0

We multiply parentheses

-3x-(2(2x-5))+15+3=0



We calculate terms in parentheses: -(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We add all the numbers together, and all the variables

-3x-(4x-10)+18=0

We get rid of parentheses

-3x-4x+10+18=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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