3-3(2-2b)=4(b-3)+4

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Solution for 3-3(2-2b)=4(b-3)+4 equation: 



3-3(2-2b)=4(b-3)+4

We move all terms to the left:

3-3(2-2b)-(4(b-3)+4)=0

We add all the numbers together, and all the variables

-3(-2b+2)-(4(b-3)+4)+3=0

We multiply parentheses

6b-(4(b-3)+4)-6+3=0



We calculate terms in parentheses: -(4(b-3)+4), so:

4(b-3)+4

We multiply parentheses

4b-12+4

We add all the numbers together, and all the variables

4b-8

Back to the equation:

-(4b-8)



We add all the numbers together, and all the variables

6b-(4b-8)-3=0

We get rid of parentheses

6b-4b+8-3=0

We add all the numbers together, and all the variables

2b+5=0

We move all terms containing b to the left, all other terms to the right

2b=-5

b=-5/2

b=-2+1/2

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