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3-2x+20=-3(x-2)
We move all terms to the left:
3-2x+20-(-3(x-2))=0
We add all the numbers together, and all the variables
-2x-(-3(x-2))+23=0
We calculate terms in parentheses: -(-3(x-2)), so:We get rid of parentheses
-3(x-2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
-2x+3x-6+23=0
We add all the numbers together, and all the variables
x+17=0
We move all terms containing x to the left, all other terms to the right
x=-17
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