3-2b=5-2(b+1)

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Solution for 3-2b=5-2(b+1) equation: 



3-2b=5-2(b+1)

We move all terms to the left:

3-2b-(5-2(b+1))=0



We calculate terms in parentheses: -(5-2(b+1)), so:

5-2(b+1)

determiningTheFunctionDomain
-2(b+1)+5

We multiply parentheses

-2b-2+5

We add all the numbers together, and all the variables

-2b+3

Back to the equation:

-(-2b+3)



We get rid of parentheses

-2b+2b-3+3=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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