3-2b/9b=1b/3b-7

Solution for 3-2b/9b=1b/3b-7 equation:

3-2b/9b=1b/3b-7

We move all terms to the left:

3-2b/9b-(1b/3b-7)=0


Domain of the equation: 9b!=0

b!=0/9

b!=0

b∈R



Domain of the equation: 3b-7)!=0

b∈R


We get rid of parentheses

-2b/9b-1b/3b+7+3=0

We calculate fractions


(-6b^2)/27b^2+(-9b^2)/27b^2+7+3=0

We add all the numbers together, and all the variables

(-6b^2)/27b^2+(-9b^2)/27b^2+10=0

We multiply all the terms by the denominator


(-6b^2)+(-9b^2)+10*27b^2=0

Wy multiply elements

(-6b^2)+(-9b^2)+270b^2=0

We get rid of parentheses

-6b^2-9b^2+270b^2=0

We add all the numbers together, and all the variables

255b^2=0

a = 255; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·255·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{510}=0$