3-2(x-5)+4x=3+4(x-2)

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Solution for 3-2(x-5)+4x=3+4(x-2) equation: 



3-2(x-5)+4x=3+4(x-2)

We move all terms to the left:

3-2(x-5)+4x-(3+4(x-2))=0

We add all the numbers together, and all the variables

4x-2(x-5)-(3+4(x-2))+3=0

We multiply parentheses

4x-2x-(3+4(x-2))+10+3=0



We calculate terms in parentheses: -(3+4(x-2)), so:

3+4(x-2)

determiningTheFunctionDomain
4(x-2)+3

We multiply parentheses

4x-8+3

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

2x-(4x-5)+13=0

We get rid of parentheses

2x-4x+5+13=0

We add all the numbers together, and all the variables

-2x+18=0

We move all terms containing x to the left, all other terms to the right

-2x=-18

x=-18/-2

x=+9

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