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3-1/6x=-1-2/5x
We move all terms to the left:
3-1/6x-(-1-2/5x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/6x-(-2/5x-1)+3=0
We get rid of parentheses
-1/6x+2/5x+1+3=0
We calculate fractions
(-5x)/30x^2+12x/30x^2+1+3=0
We add all the numbers together, and all the variables
(-5x)/30x^2+12x/30x^2+4=0
We multiply all the terms by the denominator
(-5x)+12x+4*30x^2=0
We add all the numbers together, and all the variables
12x+(-5x)+4*30x^2=0
Wy multiply elements
120x^2+12x+(-5x)=0
We get rid of parentheses
120x^2+12x-5x=0
We add all the numbers together, and all the variables
120x^2+7x=0
a = 120; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·120·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*120}=\frac{-14}{240} =-7/120 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*120}=\frac{0}{240} =0 $
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