3-1/3x=1/6x+10

Solution for 3-1/3x=1/6x+10 equation:

3-1/3x=1/6x+10

We move all terms to the left:

3-1/3x-(1/6x+10)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x+10)!=0

x∈R


We get rid of parentheses

-1/3x-1/6x-10+3=0

We calculate fractions


(-6x)/18x^2+(-3x)/18x^2-10+3=0

We add all the numbers together, and all the variables

(-6x)/18x^2+(-3x)/18x^2-7=0

We multiply all the terms by the denominator


(-6x)+(-3x)-7*18x^2=0

Wy multiply elements

-126x^2+(-6x)+(-3x)=0

We get rid of parentheses

-126x^2-6x-3x=0

We add all the numbers together, and all the variables

-126x^2-9x=0

a = -126; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-126)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-126}=\frac{0}{-252}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-126}=\frac{18}{-252}
=-1/14
$