3-(x-4)=4(x-2)

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Solution for 3-(x-4)=4(x-2) equation: 



3-(x-4)=4(x-2)

We move all terms to the left:

3-(x-4)-(4(x-2))=0

We get rid of parentheses

-x-(4(x-2))+4+3=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

-1x-(4x-8)+7=0

We get rid of parentheses

-1x-4x+8+7=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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