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3-(x+1)=2(1-x)
We move all terms to the left:
3-(x+1)-(2(1-x))=0
We add all the numbers together, and all the variables
-(x+1)-(2(-1x+1))+3=0
We get rid of parentheses
-x-(2(-1x+1))-1+3=0
We calculate terms in parentheses: -(2(-1x+1)), so:We add all the numbers together, and all the variables
2(-1x+1)
We multiply parentheses
-2x+2
Back to the equation:
-(-2x+2)
-1x-(-2x+2)+2=0
We get rid of parentheses
-1x+2x-2+2=0
We add all the numbers together, and all the variables
x=0
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