3-(d+2)=4-2(d+2)+7

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Solution for 3-(d+2)=4-2(d+2)+7 equation: 


Simplifying
3 + -1(d + 2) = 4 + -2(d + 2) + 7

Reorder the terms:
3 + -1(2 + d) = 4 + -2(d + 2) + 7
3 + (2 * -1 + d * -1) = 4 + -2(d + 2) + 7
3 + (-2 + -1d) = 4 + -2(d + 2) + 7

Combine like terms: 3 + -2 = 1
1 + -1d = 4 + -2(d + 2) + 7

Reorder the terms:
1 + -1d = 4 + -2(2 + d) + 7
1 + -1d = 4 + (2 * -2 + d * -2) + 7
1 + -1d = 4 + (-4 + -2d) + 7

Reorder the terms:
1 + -1d = 4 + -4 + 7 + -2d

Combine like terms: 4 + -4 = 0
1 + -1d = 0 + 7 + -2d
1 + -1d = 7 + -2d

Solving
1 + -1d = 7 + -2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '2d' to each side of the equation.
1 + -1d + 2d = 7 + -2d + 2d

Combine like terms: -1d + 2d = 1d
1 + 1d = 7 + -2d + 2d

Combine like terms: -2d + 2d = 0
1 + 1d = 7 + 0
1 + 1d = 7

Add '-1' to each side of the equation.
1 + -1 + 1d = 7 + -1

Combine like terms: 1 + -1 = 0
0 + 1d = 7 + -1
1d = 7 + -1

Combine like terms: 7 + -1 = 6
1d = 6

Divide each side by '1'.
d = 6

Simplifying
d = 6

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