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3-(8x-5)+(6-7x)+3=7x(5x+9-3)
We move all terms to the left:
3-(8x-5)+(6-7x)+3-(7x(5x+9-3))=0
We add all the numbers together, and all the variables
-(8x-5)+(-7x+6)-(7x(5x+6))+3+3=0
We add all the numbers together, and all the variables
-(8x-5)+(-7x+6)-(7x(5x+6))+6=0
We get rid of parentheses
-8x-7x-(7x(5x+6))+5+6+6=0
We calculate terms in parentheses: -(7x(5x+6)), so:We add all the numbers together, and all the variables
7x(5x+6)
We multiply parentheses
35x^2+42x
Back to the equation:
-(35x^2+42x)
-15x-(35x^2+42x)+17=0
We get rid of parentheses
-35x^2-15x-42x+17=0
We add all the numbers together, and all the variables
-35x^2-57x+17=0
a = -35; b = -57; c = +17;
Δ = b2-4ac
Δ = -572-4·(-35)·17
Δ = 5629
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{5629}}{2*-35}=\frac{57-\sqrt{5629}}{-70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{5629}}{2*-35}=\frac{57+\sqrt{5629}}{-70} $
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