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3-(4x+5)=7(6x-5)-(x-4)
We move all terms to the left:
3-(4x+5)-(7(6x-5)-(x-4))=0
We get rid of parentheses
-4x-(7(6x-5)-(x-4))-5+3=0
We calculate terms in parentheses: -(7(6x-5)-(x-4)), so:We add all the numbers together, and all the variables
7(6x-5)-(x-4)
We multiply parentheses
42x-(x-4)-35
We get rid of parentheses
42x-x+4-35
We add all the numbers together, and all the variables
41x-31
Back to the equation:
-(41x-31)
-4x-(41x-31)-2=0
We get rid of parentheses
-4x-41x+31-2=0
We add all the numbers together, and all the variables
-45x+29=0
We move all terms containing x to the left, all other terms to the right
-45x=-29
x=-29/-45
x=29/45
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