3-(3-x)=2-2(2-x)x=

Solution for 3-(3-x)=2-2(2-x)x= equation:

3-(3-x)=2-2(2-x)x=

We move all terms to the left:

3-(3-x)-(2-2(2-x)x)=0

We add all the numbers together, and all the variables

-(-1x+3)-(2-2(-1x+2)x)+3=0

We get rid of parentheses

1x-(2-2(-1x+2)x)-3+3=0


We calculate terms in parentheses: -(2-2(-1x+2)x), so:

2-2(-1x+2)x

determiningTheFunctionDomain
-2(-1x+2)x+2

We multiply parentheses

2x^2-4x+2

Back to the equation:

-(2x^2-4x+2)


We add all the numbers together, and all the variables

x-(2x^2-4x+2)=0

We get rid of parentheses

-2x^2+x+4x-2=0

We add all the numbers together, and all the variables

-2x^2+5x-2=0

a = -2; b = 5; c = -2;
Δ = b2-4ac
Δ = 52-4·(-2)·(-2)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3}{2*-2}=\frac{-2}{-4}
=1/2
$