3-(2w+1)-2(w-2)=5

Solution for 3-(2w+1)-2(w-2)=5 equation:

Simplifying
3 + -1(2w + 1) + -2(w + -2) = 5

Reorder the terms:
3 + -1(1 + 2w) + -2(w + -2) = 5
3 + (1 * -1 + 2w * -1) + -2(w + -2) = 5
3 + (-1 + -2w) + -2(w + -2) = 5

Reorder the terms:
3 + -1 + -2w + -2(-2 + w) = 5
3 + -1 + -2w + (-2 * -2 + w * -2) = 5
3 + -1 + -2w + (4 + -2w) = 5

Reorder the terms:
3 + -1 + 4 + -2w + -2w = 5

Combine like terms: 3 + -1 = 2
2 + 4 + -2w + -2w = 5

Combine like terms: 2 + 4 = 6
6 + -2w + -2w = 5

Combine like terms: -2w + -2w = -4w
6 + -4w = 5

Solving
6 + -4w = 5

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -4w = 5 + -6

Combine like terms: 6 + -6 = 0
0 + -4w = 5 + -6
-4w = 5 + -6

Combine like terms: 5 + -6 = -1
-4w = -1

Divide each side by '-4'.
w = 0.25

Simplifying
w = 0.25