3-((x-1)/6-x/2)=(2x-2)/3

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Solution for 3-((x-1)/6-x/2)=(2x-2)/3 equation: 


x in (-oo:+oo)

x/2-((x-1)/6)+3 = (2*x-2)/3 // - (2*x-2)/3

x/2-((x-1)/6)-((2*x-2)/3)+3 = 0

(-1*(x-1))/6+(-1*(2*x-2))/3+x/2+3 = 0

(-1*2*3*(x-1))/(2*3*6)+(-1*2*6*(2*x-2))/(2*3*6)+(3*6*x)/(2*3*6)+(2*6*3^2)/(2*3*6) = 0

3*6*x-1*2*3*(x-1)-1*2*6*(2*x-2)+2*6*3^2 = 0

18*x-30*x+30+108 = 0

30-12*x+108 = 0

138-12*x = 0

(138-12*x)/(2*3*6) = 0

(138-12*x)/(2*3*6) = 0 // * 2*3*6

138-12*x = 0

138-12*x = 0 // - 138

-12*x = -138 // : -12

x = -138/(-12)

x = 23/2

x = 23/2

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