3,1(1-3y)+y=0,4(y-14)

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Solution for 3,1(1-3y)+y=0,4(y-14) equation:



3.1(1-3y)+y=0.4(y-14)
We move all terms to the left:
3.1(1-3y)+y-(0.4(y-14))=0
We add all the numbers together, and all the variables
3.1(-3y+1)+y-(0.4(y-14))=0
We add all the numbers together, and all the variables
y+3.1(-3y+1)-(0.4(y-14))=0
We multiply parentheses
y-9.3y-(0.4(y-14))+3.1=0
We calculate terms in parentheses: -(0.4(y-14)), so:
0.4(y-14)
We multiply parentheses
0.4y-5.6
Back to the equation:
-(0.4y-5.6)
We add all the numbers together, and all the variables
-8.3y-(0.4y-5.6)+3.1=0
We get rid of parentheses
-8.3y-0.4y+5.6+3.1=0
We add all the numbers together, and all the variables
-8.7y+8.7=0
We move all terms containing y to the left, all other terms to the right
-8.7y=-8.7
y=-8.7/-8.7
y=1

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