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3+p=9(1/3
We move all terms to the left:
3+p-(9(1/3)=0
We add all the numbers together, and all the variables
p+3-(9(+1/3)=0
We add all the numbers together, and all the variables
p-(9(+1/3)+3=0
We multiply all the terms by the denominator
p*3)+3-(9(+1=0
Wy multiply elements
3p^2=0
a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{0}{6}=0$
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