3+m=3-3(m-5)-3

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Solution for 3+m=3-3(m-5)-3 equation: 



3+m=3-3(m-5)-3

We move all terms to the left:

3+m-(3-3(m-5)-3)=0



We calculate terms in parentheses: -(3-3(m-5)-3), so:

3-3(m-5)-3

determiningTheFunctionDomain
-3(m-5)+3-3

We add all the numbers together, and all the variables

-3(m-5)

We multiply parentheses

-3m+15

Back to the equation:

-(-3m+15)



We get rid of parentheses

m+3m-15+3=0

We add all the numbers together, and all the variables

4m-12=0

We move all terms containing m to the left, all other terms to the right

4m=12

m=12/4

m=3

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