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3+9x=3(2x+12)+x
We move all terms to the left:
3+9x-(3(2x+12)+x)=0
We calculate terms in parentheses: -(3(2x+12)+x), so:We get rid of parentheses
3(2x+12)+x
We add all the numbers together, and all the variables
x+3(2x+12)
We multiply parentheses
x+6x+36
We add all the numbers together, and all the variables
7x+36
Back to the equation:
-(7x+36)
9x-7x-36+3=0
We add all the numbers together, and all the variables
2x-33=0
We move all terms containing x to the left, all other terms to the right
2x=33
x=33/2
x=16+1/2
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