3+6s=4(s-3)=19

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Solution for 3+6s=4(s-3)=19 equation: 



3+6s=4(s-3)=19

We move all terms to the left:

3+6s-(4(s-3))=0



We calculate terms in parentheses: -(4(s-3)), so:

4(s-3)

We multiply parentheses

4s-12

Back to the equation:

-(4s-12)



We get rid of parentheses

6s-4s+12+3=0

We add all the numbers together, and all the variables

2s+15=0

We move all terms containing s to the left, all other terms to the right

2s=-15

s=-15/2

s=-7+1/2

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