3+6f+9f=9(f-5)+6

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Solution for 3+6f+9f=9(f-5)+6 equation: 



3+6f+9f=9(f-5)+6

We move all terms to the left:

3+6f+9f-(9(f-5)+6)=0

We add all the numbers together, and all the variables

15f-(9(f-5)+6)+3=0



We calculate terms in parentheses: -(9(f-5)+6), so:

9(f-5)+6

We multiply parentheses

9f-45+6

We add all the numbers together, and all the variables

9f-39

Back to the equation:

-(9f-39)



We get rid of parentheses

15f-9f+39+3=0

We add all the numbers together, and all the variables

6f+42=0

We move all terms containing f to the left, all other terms to the right

6f=-42

f=-42/6

f=-7

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