3+6b=4(b-3)+19

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Solution for 3+6b=4(b-3)+19 equation: 



3+6b=4(b-3)+19

We move all terms to the left:

3+6b-(4(b-3)+19)=0



We calculate terms in parentheses: -(4(b-3)+19), so:

4(b-3)+19

We multiply parentheses

4b-12+19

We add all the numbers together, and all the variables

4b+7

Back to the equation:

-(4b+7)



We get rid of parentheses

6b-4b-7+3=0

We add all the numbers together, and all the variables

2b-4=0

We move all terms containing b to the left, all other terms to the right

2b=4

b=4/2

b=2

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