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3+5/2x=x-8
We move all terms to the left:
3+5/2x-(x-8)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
5/2x-x+8+3=0
We multiply all the terms by the denominator
-x*2x+8*2x+3*2x+5=0
Wy multiply elements
-2x^2+16x+6x+5=0
We add all the numbers together, and all the variables
-2x^2+22x+5=0
a = -2; b = 22; c = +5;
Δ = b2-4ac
Δ = 222-4·(-2)·5
Δ = 524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{524}=\sqrt{4*131}=\sqrt{4}*\sqrt{131}=2\sqrt{131}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{131}}{2*-2}=\frac{-22-2\sqrt{131}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{131}}{2*-2}=\frac{-22+2\sqrt{131}}{-4} $
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