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3+4(x+5)=3(x-4)
We move all terms to the left:
3+4(x+5)-(3(x-4))=0
We multiply parentheses
4x-(3(x-4))+20+3=0
We calculate terms in parentheses: -(3(x-4)), so:We add all the numbers together, and all the variables
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
4x-(3x-12)+23=0
We get rid of parentheses
4x-3x+12+23=0
We add all the numbers together, and all the variables
x+35=0
We move all terms containing x to the left, all other terms to the right
x=-35
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