3+4(4x-4)=5-3(2x+1)

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Solution for 3+4(4x-4)=5-3(2x+1) equation: 



3+4(4x-4)=5-3(2x+1)

We move all terms to the left:

3+4(4x-4)-(5-3(2x+1))=0

We multiply parentheses

16x-(5-3(2x+1))-16+3=0



We calculate terms in parentheses: -(5-3(2x+1)), so:

5-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+5

We multiply parentheses

-6x-3+5

We add all the numbers together, and all the variables

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

16x-(-6x+2)-13=0

We get rid of parentheses

16x+6x-2-13=0

We add all the numbers together, and all the variables

22x-15=0

We move all terms containing x to the left, all other terms to the right

22x=15

x=15/22

x=15/22

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