3+3X-1=X2+2x

Solution for 3+3X-1=X2+2x equation:

3+3X-1=X2+2X

We move all terms to the left:

3+3X-1-(X2+2X)=0

We add all the numbers together, and all the variables

-(+X^2+2X)+3X+3-1=0

We add all the numbers together, and all the variables

-(+X^2+2X)+3X+2=0

We get rid of parentheses

-X^2-2X+3X+2=0

We add all the numbers together, and all the variables

-1X^2+X+2=0

a = -1; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·(-1)·2
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*-1}=\frac{-4}{-2}
=+2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*-1}=\frac{2}{-2}
=-1
$