3+3(2-3x)=8-4(x-2)

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Solution for 3+3(2-3x)=8-4(x-2) equation: 



3+3(2-3x)=8-4(x-2)

We move all terms to the left:

3+3(2-3x)-(8-4(x-2))=0

We add all the numbers together, and all the variables

3(-3x+2)-(8-4(x-2))+3=0

We multiply parentheses

-9x-(8-4(x-2))+6+3=0



We calculate terms in parentheses: -(8-4(x-2)), so:

8-4(x-2)

determiningTheFunctionDomain
-4(x-2)+8

We multiply parentheses

-4x+8+8

We add all the numbers together, and all the variables

-4x+16

Back to the equation:

-(-4x+16)



We add all the numbers together, and all the variables

-9x-(-4x+16)+9=0

We get rid of parentheses

-9x+4x-16+9=0

We add all the numbers together, and all the variables

-5x-7=0

We move all terms containing x to the left, all other terms to the right

-5x=7

x=7/-5

x=-1+2/5

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