3+2x=6(x+1)-5(x-3)

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Solution for 3+2x=6(x+1)-5(x-3) equation: 



3+2x=6(x+1)-5(x-3)

We move all terms to the left:

3+2x-(6(x+1)-5(x-3))=0



We calculate terms in parentheses: -(6(x+1)-5(x-3)), so:

6(x+1)-5(x-3)

We multiply parentheses

6x-5x+6+15

We add all the numbers together, and all the variables

x+21

Back to the equation:

-(x+21)



We get rid of parentheses

2x-x-21+3=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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