3+2v=2(2v-1)

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Solution for 3+2v=2(2v-1) equation: 



3+2v=2(2v-1)

We move all terms to the left:

3+2v-(2(2v-1))=0



We calculate terms in parentheses: -(2(2v-1)), so:

2(2v-1)

We multiply parentheses

4v-2

Back to the equation:

-(4v-2)



We get rid of parentheses

2v-4v+2+3=0

We add all the numbers together, and all the variables

-2v+5=0

We move all terms containing v to the left, all other terms to the right

-2v=-5

v=-5/-2

v=2+1/2

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