3+2b=19,b=

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Solution for 3+2b=19,b= equation: 



3+2b=19.b=

We move all terms to the left:

3+2b-(19.b)=0

We add all the numbers together, and all the variables

2b-(+19.b)+3=0

We get rid of parentheses

2b-19.b+3=0

We add all the numbers together, and all the variables

-17b+3=0

We move all terms containing b to the left, all other terms to the right

-17b=-3

b=-3/-17

b=3/17

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