3+20(k+1)=3k+6

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Solution for 3+20(k+1)=3k+6 equation: 



3+20(k+1)=3k+6

We move all terms to the left:

3+20(k+1)-(3k+6)=0

We multiply parentheses

20k-(3k+6)+20+3=0

We get rid of parentheses

20k-3k-6+20+3=0

We add all the numbers together, and all the variables

17k+17=0

We move all terms containing k to the left, all other terms to the right

17k=-17

k=-17/17

k=-1

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