3+2+2z+5-z-2=2

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Solution for 3+2+2z+5-z-2=2 equation: 



3+2+2z+5-z-2=2

We move all terms to the left:

3+2+2z+5-z-2-(2)=0

We add all the numbers together, and all the variables

z+6=0

We move all terms containing z to the left, all other terms to the right

z=-6

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