3+2(x-4)+5x=3(x-2)+4x

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Solution for 3+2(x-4)+5x=3(x-2)+4x equation: 



3+2(x-4)+5x=3(x-2)+4x

We move all terms to the left:

3+2(x-4)+5x-(3(x-2)+4x)=0

We add all the numbers together, and all the variables

5x+2(x-4)-(3(x-2)+4x)+3=0

We multiply parentheses

5x+2x-(3(x-2)+4x)-8+3=0



We calculate terms in parentheses: -(3(x-2)+4x), so:

3(x-2)+4x

We add all the numbers together, and all the variables

4x+3(x-2)

We multiply parentheses

4x+3x-6

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

7x-(7x-6)-5=0

We get rid of parentheses

7x-7x+6-5=0

We add all the numbers together, and all the variables

1!=0

There is no solution for this equation

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