3+2(x-3)=3(x+2)

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Solution for 3+2(x-3)=3(x+2) equation: 



3+2(x-3)=3(x+2)

We move all terms to the left:

3+2(x-3)-(3(x+2))=0

We multiply parentheses

2x-(3(x+2))-6+3=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

2x-(3x+6)-3=0

We get rid of parentheses

2x-3x-6-3=0

We add all the numbers together, and all the variables

-1x-9=0

We move all terms containing x to the left, all other terms to the right

-x=9

x=9/-1

x=-9

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