3+2(x+2)=20-3(2x-5)

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Solution for 3+2(x+2)=20-3(2x-5) equation: 



3+2(x+2)=20-3(2x-5)

We move all terms to the left:

3+2(x+2)-(20-3(2x-5))=0

We multiply parentheses

2x-(20-3(2x-5))+4+3=0



We calculate terms in parentheses: -(20-3(2x-5)), so:

20-3(2x-5)

determiningTheFunctionDomain
-3(2x-5)+20

We multiply parentheses

-6x+15+20

We add all the numbers together, and all the variables

-6x+35

Back to the equation:

-(-6x+35)



We add all the numbers together, and all the variables

2x-(-6x+35)+7=0

We get rid of parentheses

2x+6x-35+7=0

We add all the numbers together, and all the variables

8x-28=0

We move all terms containing x to the left, all other terms to the right

8x=28

x=28/8

x=3+1/2

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