3+2(7y-1)=-3(2y-1)+8y

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Solution for 3+2(7y-1)=-3(2y-1)+8y equation: 



3+2(7y-1)=-3(2y-1)+8y

We move all terms to the left:

3+2(7y-1)-(-3(2y-1)+8y)=0

We multiply parentheses

14y-(-3(2y-1)+8y)-2+3=0



We calculate terms in parentheses: -(-3(2y-1)+8y), so:

-3(2y-1)+8y

We add all the numbers together, and all the variables

8y-3(2y-1)

We multiply parentheses

8y-6y+3

We add all the numbers together, and all the variables

2y+3

Back to the equation:

-(2y+3)



We add all the numbers together, and all the variables

14y-(2y+3)+1=0

We get rid of parentheses

14y-2y-3+1=0

We add all the numbers together, and all the variables

12y-2=0

We move all terms containing y to the left, all other terms to the right

12y=2

y=2/12

y=1/6

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