3+2(7-4n)=-(n+4)-4n

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Solution for 3+2(7-4n)=-(n+4)-4n equation:



3+2(7-4n)=-(n+4)-4n
We move all terms to the left:
3+2(7-4n)-(-(n+4)-4n)=0
We add all the numbers together, and all the variables
2(-4n+7)-(-(n+4)-4n)+3=0
We multiply parentheses
-8n-(-(n+4)-4n)+14+3=0
We calculate terms in parentheses: -(-(n+4)-4n), so:
-(n+4)-4n
We add all the numbers together, and all the variables
-4n-(n+4)
We get rid of parentheses
-4n-n-4
We add all the numbers together, and all the variables
-5n-4
Back to the equation:
-(-5n-4)
We add all the numbers together, and all the variables
-8n-(-5n-4)+17=0
We get rid of parentheses
-8n+5n+4+17=0
We add all the numbers together, and all the variables
-3n+21=0
We move all terms containing n to the left, all other terms to the right
-3n=-21
n=-21/-3
n=+7

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