3+2(4+7b)=109

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Solution for 3+2(4+7b)=109 equation: 



3+2(4+7b)=109

We move all terms to the left:

3+2(4+7b)-(109)=0

We add all the numbers together, and all the variables

2(7b+4)+3-109=0

We add all the numbers together, and all the variables

2(7b+4)-106=0

We multiply parentheses

14b+8-106=0

We add all the numbers together, and all the variables

14b-98=0

We move all terms containing b to the left, all other terms to the right

14b=98

b=98/14

b=7

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