3+2(3x+1)=3+2(2x-1)

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Solution for 3+2(3x+1)=3+2(2x-1) equation: 



3+2(3x+1)=3+2(2x-1)

We move all terms to the left:

3+2(3x+1)-(3+2(2x-1))=0

We multiply parentheses

6x-(3+2(2x-1))+2+3=0



We calculate terms in parentheses: -(3+2(2x-1)), so:

3+2(2x-1)

determiningTheFunctionDomain
2(2x-1)+3

We multiply parentheses

4x-2+3

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

6x-(4x+1)+5=0

We get rid of parentheses

6x-4x-1+5=0

We add all the numbers together, and all the variables

2x+4=0

We move all terms containing x to the left, all other terms to the right

2x=-4

x=-4/2

x=-2

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